Rabu, 26 September 2018


TUGAS ELEKTRONIKA DIGITAL
                                               
NAMA                          : M.Makhsun febriyanto
NIM                             : 1703030022
PRODI                          : T.Elektro


a)      2710   :  (11011)2



b)110102 = (32)8
 
  11                            010
1X21+1X20                 0X22 + 1 X 21 +0 X 20
2 + 1                         0 + 2 + 0
=  3                           = 2


c)    638 = 5110

6X81 + 3X80
48 + 3
= 51

d)6FE16 = (010111111110)2

6     = 0101
F     = 1111
E     = 1110

e)   11011102 = (110)10

         = 1X26 + 1X25 + 0X24 + 1X23 + 1X22 + 1X21 + 0X20
   = 64+32+0+8+4+2+0
   = 110

f)    (517)8 = 33510

= 5X82 + 1X81 + 7X80
= 320 + 8 + 7
= 335

g)   D3A16 = 64728

D = 1101
3 = 0011
A = 1010

110100111010
110       100       111       010
  6            4            7            2

h)478 = 1001112


Jadi, 478 = 1001112

i)    7568 = 1EE16

7568 = 1111011102
           1110 = E
           1110 = E
           0001 = 1
Jadi, 7568 = 1EE16

j)    4C16 = 010011002

      4 = 0100
      C = 1100
Jadi, 4C16 = 010011002

Tidak ada komentar:

Posting Komentar